`(sin 36^(@))/( cos 54^(@))-( sin 54^(@))/( cos 36^(@))` का मान ज्ञात करो ।

Explanation

`( sin 36^(@))/( cos 54^(@))-( sin 54^(@))/( cos 36^(@))=(sin (90^(@)-54^(@)))/( cos 54^(@))-( sin (90^(@)-36^(@)))/( cos 36^(@))=( cos 54^(@))/( cos 54^(@))-( cos 36^(@))/( cos 36^(@))=1-1=0" " [:' sin (90^(@) - theta )=sin theta , cos (90^(@)- theta )= sin theta ]`