The solubility of `PbCl_(2)` in water is 0.01 M `25^(@)` C. Its maximum concentration in 0.1 M NaCl will be :

The solubilituy of PbCI_(2) in water is 0.01M 25^(@)C . Its maximum concentration in 0.1M NaCI will be:

The solubility of PbCl_2 in water is 0.01 M at 25^@C it maximum concentration in 0.1M NaCl will be :

If the maximum concentration of PbCl_2 in water is 0.01 M at 25^@C , its maximum concentration in 0.1 M NaCl will be

Suppose the solubilities of AgCl in water, in 0.01 M CaCl_(2) solution, in 0.01 M NaCl solution and in 0.05 M AgNO_(3) solution are S_(1), S_(2), S_(3) and S_(4) respectively. The correct order of these solubilities is

The solubility product of AgCI in water is 1.5xx10^(-10) . Calculate its solubility in 0.01M NaCI .

The solubility product of AgCl in water is 1.5xx10^(-10) .Calculate its solubility in 0.01 M NaCl aqueous solution.

The solubility of CdSO_4 in water is 8.0 xx 10^(-4) mol L^(-1) . Its solubility in 0.01 M H_2SO_4 solution is ........... Xx 10^(-6)" mol L"^(-1) . (Round off to the Nearest Integer). (Assume that solubility is much less than 0.01M).