Mahendra nad Virat are sitting at a distance of 1 metre from each other. Their masses are 75 kg and 80 kg respectively. What is the gravitational force between them ?
`G=6.67xx10^(-11)N.m^(2)//kg^(2)`.

Explanation

Given: `r=1m`
`m_(1)=75kg`
`m_(2)=80kg`
`G=6.67xx10^(-11)Nm^(2)//kg^(2)`
To find: Force `(F)=?`
Frormula:`F=(Gm_(1)m_(2))/(r^(2))`
`F=(6.67xx10^(-11)xx75xx80)/(1^(2))`
`F=6.67xx10^(-11)xx(6xx10^(3))`
`=40.02xx10^(-8)`
`=4.00xx10^(-7)N`
The gravitational force between Mahendra and Virat is `4.002xx10^(-7)N`