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The mass of the earth is 6 xx 10^(24) ...

The mass of the earth is ` 6 xx 10^(24) kg.` The distance between the earth and the sun is ` 1.5 xx 10^(11)` m. If the gravitational force between the two is ` 3.5 xx 10^(22)` N, what is the mass of the Sun ? Use ` G = 6.7 xx 10^(-11) N.m^(2) kg^(-2)` gt

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Given `m_(1)=6xx10^(24)kg`
`r=1.5xx10^(11)m`
`F=3.5x10^(22)N`
`G=6.7xx10^(-1)Nm^(2)//kg^(2)`
To find `: m_(2)=?`
Formula `F=(Gm_(1)m_(2))/(r^(2))`
Solution: `(Fr^(2))/(Gm_(1))=m_(2)`
`m_(2)=(3.5xx10^(22)xx(1.5xx10^(11))^(2))/(6.7x10^(-11)xx6xx10^(24))`
`=(7.875xx10^(44))/(40.2xx10^(13))`
`=7.875/40xx10^(31)` ltbr. `=0.196xx10^(31)kg`
`=1.96xx10^(30)kg`
The mass of the Sun is `1.96xx10^(30)kg`
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