A gravitational force of `4.002xx10^(-7)` N is acting between mahendra (75kg) and virat (80kg). Assuming that the bench on which mahendra is sitting is frictionless, starting with zero velocity , what will be mahendra's velocity of motion towards virat after 1s? Will this velocity change with time and how ?

Explanation

Given : Force on mahendra (F) `=4.002xx10^(-7)N`
Mahendra's mass (m) = 75kg
To find : Velocity (v)
Formula : (i) F=ma
(ii) v=u+at
Calculation : from formula (i) ,
`a=F/m = (4.002xx10^(-7))/(75) = 5.34xx10^(-9) m//s^2`
As mahendra is sitting on the bench, his initial velocity is zero (u=0) Assuming the bench to be frictionless , from formula (ii)
`v=0+5.34xx10^(-9)xx1`
`therefore v=5.34xx10^(-9) m//s`
As mahendra is moving towards virat, the distance between them decreases causing an increase in gravitational force.
For a given mass , gravitational force being directly , acceleration increases.
`a=F/m`
As acceleration increases, the velocity increases.