Home
Class 10
PHYSICS
Two planets move around the sun. The per...

Two planets move around the sun. The periodic times and the mean radii of the orbits are `T_(1), T_(2)` and `r_(1) r_(2)` respectively. The ratio `T_(1)//T_(2)` is equal to

Text Solution

Verified by Experts

The correct Answer is:
F
Two planets move around the sun. The periodic times and the mean radii of the orbits are `T_1, T_2 " and " r_1, r_2` respectively. Then the ratio `T_1//T_2 " is equal to " (r_1//r_2)^(3//2)`
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    TARGET PUBLICATION|Exercise ODD ONE OUT|3 Videos

  • GRAVITATION

    TARGET PUBLICATION|Exercise COMPLETE THE ANALOGY|4 Videos

  • GRAVITATION

    TARGET PUBLICATION|Exercise NAME THE FOLLOWING|6 Videos

  • ENVIRONMENTAL MANAGEMENT

    TARGET PUBLICATION|Exercise APPLY OUR KNOWLEDGE|28 Videos

  • HEAT

    TARGET PUBLICATION|Exercise Values to remember|10 Videos

Similar Questions

Explore conceptually related problems

Two planets revolve round the sun with frequencies N_(1) and N_(2) revolutions per year. If their average orbital radii be R_(1) and R_(2) respectively, then R_(1)//R_(2) is equal to

A and B are two satellite revolving around the earth in circular orbits with radii R_(A) and R_(B) . Their periods T_(A) and T_(B) are 8 h and 1 h respectively. Then the ratio of (R_(A)//R_(B)) is equal to

Two spherical black bodies of radii R_(1) and R_(2) and with surface temperature T_(1) and T_(2) respectively radiate the same power. R_(1)//R_(2) must be equal to

A planet of mass M, has two natural satellites with masses m1 and m2. The radii of their circular orbits are R_(1) and R_(2) respectively. Ignore the gravitational force between the satellites. Define v_(1), L_(1), K_(1) and T_(1) to be, respectively, the orbital speed, angular momentum, kinetic energy and time period of revolution of satellite 1 , and v_(2), L_(2), K_(2) and T_(2) to be he corresponding quantities of satellite 2. Given m_(1)//m_(2) = 2 and R_(1)//R_(2) = 1//4 , match the ratios in List-I to the numbers in List-II.

A planet of mass m is moving in an elliptical orbit about the sun (mass of sun = M). The maximum and minimum distances of the planet from the sun are r_(1) and r_(2) respectively. The period of revolution of the planet wil be proportional to :

Two planets are at distance R_1 and R_2 from the Sun. Their periods are T_1 and T_2 then (T_1/T_2)^2 is equal to

The distances of two planets A nad B from the sun are 10^(12)m and 10^(11)m and their periodic times are T_(A) and T_(B) respectively. If their orbits are assumed to be circular, then the ratio of their periodic times ((T_(A))/(T_(B))) will be

A planet of mass m moves around the Sun of mass Min an elliptical orbit. The maximum and minimum distance of the planet from the Sun are r_(1) and r_(2) , respectively. Find the relation between the time period of the planet in terms of r_(1) and r_(2) .

Astronomers observe two separate solar systems each consisting of a planet orbiting a sun. The two orbits are circular and have the same radius R . It is determined that the planets have angular momenta of the same magnitude L about their suns, and that the orbital periods are in the ratio of three to one, i.e. T_(1)=3T_(2) . The ratio m_(1)//m_(2) of the masses of the two planets is