Home
Class 10
PHYSICS
Doctor has presecribed a lens having pow...

Doctor has presecribed a lens having power + 1.5D. What will be the focal length of the lens ? What is the type of the lens and what must be the defect of vision ?

Text Solution

Verified by Experts

The correct Answer is:
The prescribed lens is convex lens of focal length +0.67 m and the defect in vision is hypermetropia (farsightedness).

Given: Power (P) =+1.5 D
To find: Focal length (f)
Formula: `P=(1)/(f(m))`
Calculation: From formula,
`f=(1.5)=+0.67 m`
The prescribed lens is convex lens as the focal length is positive. Convex lens has positive focal length and it is used for the correction of farsightedness or hypermetropia. Thus, the defect in vision is hypermetropia (farsightedness).
Promotional Banner

Topper's Solved these Questions

  • LENSES

    TARGET PUBLICATION|Exercise Choose the correct alternative|11 Videos
  • LENSES

    TARGET PUBLICATION|Exercise Complete the paragraph|1 Videos
  • LENSES

    TARGET PUBLICATION|Exercise Chapter Assessment|21 Videos
  • HEAT

    TARGET PUBLICATION|Exercise Values to remember|10 Videos
  • MODEL QUESTION PAPER (PART -1 )

    TARGET PUBLICATION|Exercise Questions|21 Videos

Similar Questions

Explore conceptually related problems

Doctor has prescribed a lens having power +2 D . What will be the focal length of the lens ? What is the type of the lens and what must be the defect of vision ?

Amar is using spectacles with power - 2.5 D. What will be the focal length (in cm) of the lens used in spectacles? What is the type of the lens and what must be the defect of vision Amar is suffering from?

Power of a lens is + 3 D. What will be the focal length of the lens?

A focal length of a lens 10cm. What is power of a lens in dipotre?

A lens has a focal length of, -10cm . What is the power of the lens and what is its nature?

A thin lens has focal length of, -25 cm. What is the power of the lens and what is its nature?

What will be the focal length of a lens whose power is given as + 2.0 D ?

If f is focal length of the lens, then the power of a lens is equal to