Home
Class 10
PHYSICS
Calculate the time taken by a satellite ...

Calculate the time taken by a satellite for one revolution revolution revolving at a height of 6400 km above the earth's surface with velocity 5.6 km/s .

Promotional Banner

Topper's Solved these Questions

  • SPACE MISSIONS

    TARGET PUBLICATION|Exercise Chapter Assessment (Chosse the correct alternative.)|3 Videos
  • SOCIAL HEALTH

    TARGET PUBLICATION|Exercise CHAPTER ASSESSMENT|3 Videos
  • TOWARDS GREEN ENERGY

    TARGET PUBLICATION|Exercise Chapter Assessment|2 Videos

Similar Questions

Explore conceptually related problems

Satellite revolving around the earth at a height of 400 Km above the earth's surface has a time period of about

Hubble telescope revolves around the earth in a orbit at a height 540 km above the earth 's surface. Find the velcoity of the telescope.

Suppose the satellite is revolving at a height of 35780 km above the earth's surface with velocity 3.08 km/s . How much time the satellite will take to complete one revolution around the earth ?

Calculate the percentage decrease in the weight of a body when it is taken to a height of 40 km above the earth's surface. Radius of earth = 6,400 km.

The time period of the earth's satellite revolving at a height of 35800 km is

Taking the earth to be a uniform sphere of radius 6400 km and the value of g at the surface to be 10ms^(-2) , calculate the energy needed to raise a satellite of mass 2000 kg to a height of 800 km a above the earth's surface and to set it into circular orbit at that altitude.

Calculate the value of acceleration due to gravity at a point a. 5.0 km above the earth's surface and b. 5.0 km below the earth's surface. Radius of earth =6400 km and the value of g at the surface of the earth is 9.80 ms^2

How much time would a satellite in an orbit at a height of 35780 km above the earth's surface take to complete one revolution around the earth , if the mass of the earth were four times its original mass ?

A remote sensing satellite of the earth revolves in a circular orbit at a height of 250 km above the earth's surface. What is the (i) orbital speed and (ii) period of revolution of the satellite ? Radius of the earth, R=6.38xx10^(6) m, and acceleration due to gravity on the surface of the earth, g=9.8 ms^(-2) .

A geostationary satellite orbits around the earth in a circular orbit of radius 36,000 km. then the time period of a spy satellite orbiting a frw hundred km (600 km) above the earth's surface (R=6400 km) will approximately be