Home
Class 10
MATHS
Find the mean of the data given in the f...

Find the mean of the data given in the following table.
`{:("Class",0-20,20-40,40-60,60-80,80-100),("Frequency"," "6," "4," "5," "7," "3):}`

Text Solution

AI Generated Solution

The correct Answer is:
To find the mean of the given data, we will follow these steps: ### Step 1: Identify the Class Intervals and Frequencies We have the following class intervals and their corresponding frequencies: - Class Intervals: 0-20, 20-40, 40-60, 60-80, 80-100 - Frequencies (f): 6, 4, 5, 7, 3 ### Step 2: Calculate the Midpoint (xi) for Each Class Interval The midpoint (xi) for each class interval is calculated as: \[ xi = \frac{\text{Lower Limit} + \text{Upper Limit}}{2} \] Calculating the midpoints: - For 0-20: \( xi = \frac{0 + 20}{2} = 10 \) - For 20-40: \( xi = \frac{20 + 40}{2} = 30 \) - For 40-60: \( xi = \frac{40 + 60}{2} = 50 \) - For 60-80: \( xi = \frac{60 + 80}{2} = 70 \) - For 80-100: \( xi = \frac{80 + 100}{2} = 90 \) ### Step 3: Create a Table of Frequencies and Midpoints | Class Interval | Frequency (f) | Midpoint (xi) | |----------------|---------------|----------------| | 0 - 20 | 6 | 10 | | 20 - 40 | 4 | 30 | | 40 - 60 | 5 | 50 | | 60 - 80 | 7 | 70 | | 80 - 100 | 3 | 90 | ### Step 4: Calculate the Product of Frequency and Midpoint (fi * xi) Now, we will calculate \( fi \times xi \) for each class interval: - For 0-20: \( 6 \times 10 = 60 \) - For 20-40: \( 4 \times 30 = 120 \) - For 40-60: \( 5 \times 50 = 250 \) - For 60-80: \( 7 \times 70 = 490 \) - For 80-100: \( 3 \times 90 = 270 \) ### Step 5: Create a Table of Frequencies, Midpoints, and their Products | Class Interval | Frequency (f) | Midpoint (xi) | fi * xi | |----------------|---------------|----------------|---------| | 0 - 20 | 6 | 10 | 60 | | 20 - 40 | 4 | 30 | 120 | | 40 - 60 | 5 | 50 | 250 | | 60 - 80 | 7 | 70 | 490 | | 80 - 100 | 3 | 90 | 270 | ### Step 6: Calculate the Sums Now, we will calculate the total of frequencies and the total of \( fi \times xi \): - \( \Sigma f = 6 + 4 + 5 + 7 + 3 = 25 \) - \( \Sigma (fi \times xi) = 60 + 120 + 250 + 490 + 270 = 1190 \) ### Step 7: Calculate the Mean The mean (x̄) is calculated using the formula: \[ \text{Mean} = \frac{\Sigma (fi \times xi)}{\Sigma f} \] Substituting the values: \[ \text{Mean} = \frac{1190}{25} = 47.6 \] ### Conclusion Therefore, the mean of the data is **47.6**. ---
Promotional Banner

Topper's Solved these Questions

  • STATISTICS

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise Challenging Questions|2 Videos
  • SIMILARITY

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise SUBJECTIVE TYPE|20 Videos
  • THEOREMS

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise CIRCLE|15 Videos

Similar Questions

Explore conceptually related problems

Calculate mode from the following data : {:("Class Interval",0-10,10-20,20-30,30-40,40-50),("Frequency"," "2," "5," "7," "5," "2):}

Calculate mean , median and mode from the following data : {:("Class Interval",30-40,40-50,50-60,60-70,70-80,80-90),("Frequency"," "18," "37," "45," "27," "15," "8):}

Calculate mode from the following data : {:("Class Interval",30-40,40-50,50-60,60-70,70-80,80-90,90-100),("Frequency"," "3," "4," "6," "10," "6," "4," "3):}

Caculate mode of the following data : {:("Marks",0-5,5-10,10-20,20-40,40-60,60-80,80-90,90-100),("Number of Students"," "5," "7," "9," "25" "," "30," "24," "8," "6):}

Find out the arithmetic mean by the Step-deviation Method of the following: {:("Class Interval",0-10,10-20,20-30,30-40,40-50,50-60,60-70,70-80),("Frequency "," "12," "16," "32," "52," "42," "32," "18," "12):}

Find the missing frequency of the group 20-30 when the median is 28. {:("Class Interval",0-10,10-20,20-30,30-40,40-50),("Frequency"," "5," "8," "?," "16," "6):}

Obtain the mean , median and mode of the following data : {:("Marks",0-10,10-20,20-30,30-40,40-50,50-60,60-70,70-80),("Number of Students"," "5," "7," "15," "25," "20," "15," "8," "5):}

Find the mean deviation from the mean of the following data: Classes:,10-20,20-30,30-4040-50,50-60,60-70,70-80 frequency,2,3,8,14,8,3,2

NAVNEET PUBLICATION - MAHARASHTRA BOARD-STATISTICS-EXAMPLES FOR PRACTICE (MCQs)
  1. Find the value of Sigmaf(i) d(i) for the following information. (i) ...

    Text Solution

    |

  2. Find the value of bar u for the following information : (i) A = 22.5...

    Text Solution

    |

  3. Find the mean of the data given in the following table. {:("Class",0...

    Text Solution

    |

  4. The following table shows the percentage of vehicles passing a signal....

    Text Solution

    |

  5. The age group of the number of persons in the age group who donated bl...

    Text Solution

    |

  6. Find barX by step deviation method : Given : A = 2200. " "Sigma ...

    Text Solution

    |

  7. The mean of the data by step deviation method is Rs. 1390. Find the as...

    Text Solution

    |

  8. The mean of the data by step deviation method is 1896 . Find the value...

    Text Solution

    |

  9. For each of the following frequencies distribution draw histogram : (...

    Text Solution

    |

  10. A survey was conducted in Aadarsh Vidyalaya to know the inclination ...

    Text Solution

    |

  11. The cost of living index and the number of weeks are given in the foll...

    Text Solution

    |

  12. Marks ( out of 50) obtaned in Mathematics by 100 students is given in ...

    Text Solution

    |

  13. Calculate the mean for the following data :

    Text Solution

    |

  14. Calculate the mean of the following frequency distribution : (Use step...

    Text Solution

    |

  15. Find the mode for the following :

    Text Solution

    |

  16. Draw a frequency polygon from the information given in the following t...

    Text Solution

    |

  17. The following table shows the number of patients of differents age gro...

    Text Solution

    |

  18. The number of hours spent by a school boy in different activities in a...

    Text Solution

    |

  19. The percentage of expenditure on different heads in a budget of a stat...

    Text Solution

    |

  20. The following table is based on the marks of the first term examinatio...

    Text Solution

    |