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In figure, if PQ=6,QR=10,PS=8, find TS....

In figure, if PQ=6,QR=10,PS=8, find TS.

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The correct Answer is:
4
PR=PQ+QR`" " ""…….."( P-Q-R)`
`:.PR=6+10`
`:.PR=16`
Chord ST and chord QR intersect at point P outside the circle.
`:.` by theorem of external division of chords,
`PSxx PT=PQxx PR`
`:.8xxPT=6xx16`
`PT=(6xx16)/(8)`
`:.PT=12`
PS+TS=PT`" ""........"(P-S-T)`
`:.8+TS=12`
`:.TS=12-8`
`:.TS=4`
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