If `tan theta = 1`, find tha value of `(sintheta + costheta)/(sectheta + cosectheta)`.

Explanation

`tan theta = 1`
we know that, `tan 45^@ = 1`
`therefore theta = 45^@`
`sintheta = sin 45^@ = 1/(sqrt(2))`
`cos theta = cos 45^@ = 1/sqrt2`
`sec theta = sec 45^@ = sqrt(2)`
` cosec theta = cosec 45^@ = sqrt(2)`
`(sintheta + costheta)/(sectheta + cosectheta)=(sin45^@ + cos45^@)/(sec45^@ + cosec45^@)` ltbgt` =((1)/(sqrt2)+(1)/(sqrt2))/(sqrt2+sqrt2)`
`=((2/(sqrt(2))))/(2sqrt(2))`
`= (2)/(sqrt(2))divsqrt(2)`
`= (2)/(sqrt(2)) xx (1)/2(sqrt(2))`
`=1/2`
` (sintheta + costheta)/(sectheta + cosectheta)=1/2`.