Two poles of heights 18 meter and 7 meter are erected on a ground. The length of the wire fastened at their tops in 22 meter. Find the angle made by the wire with the horizontal.

Explanation

Let seg AB and seg Ce represent the two poles.
AC represents the wire and seg AE`bot`seg CD
… C-E-D.AB = 7 m, CD = 18m, AC =22 m.
`angleCAE` is the angle made by the wire with the horizontal.
Let `angleCAE = theta`.
`squareABDE` is a rectangle.
De = AB = 7 m
....(Opposite sides fo rectangle are equal)
CE + ED = CD ...(C-E-D)
`therefore` CE + 7 = 18
`therefore` CE = 18-7
`therefore` CE = 11 m
In right angled `triangleCEA`,
`sin theta = (CE)/(AC) ` ...(By definition )n
`therefore sin theta = 11/22`
We know that, `sin 30^@ = 1/2`
`therefore theta = 30`
The angle made by the wire with horizontal is `30^@`.