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A body is thrown vertically upward with ...

A body is thrown vertically upward with a velocity of 9.8 m/s. Calculate the maximum height attained by the body. `(g=9.8m//s^(2))`

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AI Generated Solution

To calculate the maximum height attained by a body thrown vertically upward with an initial velocity of 9.8 m/s, we can use the equations of motion. Here’s a step-by-step solution: ### Step 1: Identify the known values - Initial velocity (u) = 9.8 m/s - Final velocity (v) at maximum height = 0 m/s (since the body stops rising at the maximum height) - Acceleration due to gravity (g) = -9.8 m/s² (negative because it acts downward) ### Step 2: Use the third equation of motion ...
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Knowledge Check

  • If a ball is thrown upward with a velocity of 6 m/s. The maximum height attained by the particle is

    A
    1.8 m
    B
    3.6 m
    C
    5.4 m
    D
    none
  • If a body is thrown up with the velocity of 15 m/s then maximum height attained by the body is (g = 10m//s)

    A
    `11.25m`
    B
    `16.2m`
    C
    `24.5m`
    D
    `7.62m`
  • A particle is thrown vertically upward. Its velocity at half of the height is 10 m/s. Then the maximum height attained by it : - (g=10 m//s^2)

    A
    8 m
    B
    20 m
    C
    10 m
    D
    16 m
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    A body is thrown up with a velocity of 20 m/s. The maximum height attained by it is approximately

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