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A body is thrown vertically upward with a velocity of 9.8 m/s. Calculate the maximum height attained by the body. `(g=9.8m//s^(2))`

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To calculate the maximum height attained by a body thrown vertically upward with an initial velocity of 9.8 m/s, we can use the equations of motion. Here’s a step-by-step solution: ### Step 1: Identify the known values - Initial velocity (u) = 9.8 m/s - Final velocity (v) at maximum height = 0 m/s (since the body stops rising at the maximum height) - Acceleration due to gravity (g) = -9.8 m/s² (negative because it acts downward) ### Step 2: Use the third equation of motion ...
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NAVNEET PUBLICATION - MAHARASHTRA BOARD-GRAVITATION -Solve the following examples/numerical problems :
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