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Assuming the acceleration in Example 2 a...

Assuming the acceleration in Example 2 above remains constant, how long will Mahendra take to move 1 cm towards Virat ?

Text Solution

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Here, `u=0`
`therefore s=ut+(1)/(2)at^(2)=0+(1)/(2)at^(2)`
`therefore t=sqrt((2s)/(a))=sqrt((2xx1xx10^(-2)m)/(5.34xx10^(-9)m//s^(2)))`
`=sqrt(0.3745xx10^(7)s^(2))=sqrt(3.745xx10^(6))s`
= 1935 s = 32 minutes 15 seconds.
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