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Write the proper answer in the square. ...

Write the proper answer in the square.

`"If "F=(Gm_(1)m_(2))/(d^(2))" then F = _____________"`

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`F=(Gm_(1)m_(2))/(9d^(2))`
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Write proper answer in the box : If F=(Gm_1m_2)/d^2 then F=

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Assertion : Mass of the rod AB is m_(1) and of particle P is m_(2) . Distance between centre of rod and particle is r. Then the gravitational force between the rod and the particle is F=(Gm_(1)m_(2))/(r^(2)) Reason : The relation F=(Gm_(1)m_(2))/(r^(2)) can be applied directly only to find force between two particles.

Gravitational force, F=Gm_(1)m_(2)//r.

The force of attraction between two point magnetic poles is directly proportional to the product of their pole strengths and inversely proportional to the square of the distance between them. i.e. F prop (m_(1)m_(2))/(d^(2)) rArr F= (Km_(1)m_(2))/(d^(2)) . Where K is a constant, m_(1) and m_(2) are pole strengths and 'd' is the distance between them. This is called Coulomb's law Using the above information, answer the following questions. The force between two poles (m_(1) and m_(2)) in air which are separated by a distance 'd' is F. If the distance is doubled, the force between the poles in air now is ____

The force of attraction between two point magnetic poles is directly proportional to the product of their pole strengths and inversely proportional to the square of the distance between them. i.e. F prop (m_(1)m_(2))/(d^(2)) rArr F= (Km_(1)m_(2))/(d^(2)) . Where K is a constant, m_(1) and m_(2) are pole strengths and 'd' is the distance between them. This is called Coulomb's law Using the above information, answer the following questions. The force between two poles (m_(1) and m_(2)) in air which are separated by a distance 'd' is F. If m_(1) is halved and m_(2) is doubled and the distance is same i.e., d, the force now is ____

The force of attraction between two point magnetic poles is directly proportional to the product of their pole strengths and inversely proportional to the square of the distance between them. i.e. F prop (m_(1)m_(2))/(d^(2)) rArr F= (Km_(1)m_(2))/(d^(2)) . Where K is a constant, m_(1) and m_(2) are pole strengths and 'd' is the distance between them. This is called Coulomb's law Using the above information, answer the following questions. When the distance between two magnetic poles is halved, the force between them will become

NAVNEET PUBLICATION - MAHARASHTRA BOARD-GRAVITATION -QUESTIONS & ANSWERS
  1. For a freely falling object we can write Newton's second equation of ...

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  2. Write the proper answer in the square. "If this F = x ...

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  3. Write the proper answer in the square. "If "F=(Gm(1)m(2))/(d^(2))...

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  4. The gravitational force between two particles separated by a distance ...

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  5. In the usual notation, the acceleration due to gravity at a height h f...

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  6. The SI unit of the universal constant of gravitation is …………. .

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  7. The escape velocity of a body from the earth's surface, v("esc")=……….....

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  8. How much will a person with 72 N weight on the earth, weigh on the moo...

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  9. What will be the weight of a person on the earth, who weights 9 N on t...

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  10. If the separation between two particles is doubled, the gravitational ...

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  11. The CGS unit of the universal constant of gravitation is the dyne cm^(...

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  12. At the centre of the earth , the value of the acceleration due to grav...

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  13. The weight of a body is minimum at the poles.

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  14. Mass is a vector quantity.

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  15. Weight is a vector at the equator.

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  16. g has maximum value at the equator.

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  17. Outside the earth, g varies as 1//(R+h)^(2).

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  18. The value of G changes from place to place.

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  19. The value of g increases with altitude.

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  20. The escape velocity of a body does not depend on the mass of the body.

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