If the body in Ex. (26) performs uniform circular motion around the earth at a hight of 3600 km from the earh's surface, what will be its gravitational potential energy?

Explanation

Here, `h=3600km=3.6xx10^(6)m`
`therefore" The gravitational potential energy of the body "`
`-(GMm)/(R+h)`
`=-(6.67xx10^(-11)N.m^(2)//kg^(2)xx6xx10^(24)kgxx10kg)/((6.4xx10^(6)+3.6xx10^(6))m)`
`=-(6.67xx6xx10^(14))/(10xx10^(6))J=-4.002xx10^(8)J.`