Write the balanced equations for the following reactions :
* (i) `H_(2)S_(2)O_(7_((1)))+H_(2)O_((1))rarrH_(2)SO_(4_((1)))`

Explanation

Step 1 : Rewrite the given equation as it is `H_(2)S_(2)O_(7_((1)))+H_(2)O_((1))rarrH_(2)SO_(4_((1)))`
Step 2 : Write the number of atoms of each element in the unbalanced equation on both sides of equations.

Step 3 : To equalise the nuber of hydrogen atoms , sulphur atoms and oxygen atoms we use 2 the coefficient or factor in the product.

Now the equation becomes `H_(2)S_(2)O_(7)+H_(2)Orarr2H_(2)SO_(4)`
Now , count the atoms of each element on both sides of the equation. The number of atoms on both sides are equal. Hence , the balanced equation is
`H_(2)S_(2)O_(7)+H_(2)Orarr2H_(2)SO_(4)`
Now indicate physical states of the reactants and products.
`H_(2)S_(2)O_(7_((1)))+H_(2)O_((1))rarr2H_(2)SO_(4_((1)))`