Write the balanced equations for the following reactions : * (iv) `H_(2)SO_(4_((aq)))+NaOH_((aq))rarrNa_(2)SO_(4_((aq)))+H_(2)O_((1))`

Explanation

Step 1 : Rewrite the given equation as it is
`H_(2)SO_(4_((aq)))+NaOH_((aq))rarrNa_(2)SO_(4_((aq)))+H_(2)O_((1))`
Step 2 : Write the number of atoms of each element in the unbalanced equation on both sides of the equation.

The number of oxygen atoms involved in different compounds on both sides (reactants and products ) are equal . Therefore , balance the number of atoms of the second element, sodium.
Step 3 : To balance the number of sodium atoms :
To equalise the number of sodium atoms, we use 2 as the factor of NaOH in the reactants . Now , the partly balanced equation becomes as follows : lt brgt `H_(2)SO_(4)+2NaOHrarrNa_(2)SO_(4)+H_(2)O`
Step 4 : Now , balance the number of hydrogen atoms :
To equalise the number of hydrogen atoms, we use 2 as the factor of `H_(2)O` in the products . The equation then becomes
`H_(2)SO_(4)+2NaOHrarrNa_(2)SO_(4)+2H_(2)O`
Now , count the atoms of each element on both sides of the equation . The number of atom on both sides are equal . Hence , the balanced equation is
`H_(2)SO_(4)+2NaOHrarrNa_(2)SO_(4)+2H_(2)O`
Now indicate the physical states of the reactan and the produts .
`H_(2)SO_(4_((aq)))+2NaOH_((aq))rarrNa_(2)SO_(4)+2H_(2)O_((1))`