Write the balanced equations for the following reactions :
(vi) Calcium chloride + Sulphuric acid `rarr` Calcium sulphate + H ydrogen chloride.

Explanation

Step 1 : Write the chemical equation from the given word equation .
`CaCl_(2)+H_(2)SO_(4)rarrCaSO_(4)+HCl`
Step 2 : Write the number of atoms of each element the unbalanced on both sides of equation.

Step 3 : In the given equation `H_(2)SO_(4)` is a compound and it contains hydrogen element . On the left hand side there are two hydrogen atoms and on the right side one hydrogen atom . Equalise H atoms on both sides.
To equalise the number of hydrgen atoms we use 2 as the factore in the product so that the number of H atoms on both sides are equal. Therefore , the equation becomes
`CaCl_(2)+H_(2)SO_(4)rarrCaSO_(4)+2HCl`
Now , indicate the physical of the reactants and products.
`CaCl_(2_((s)))+H_(2)SO_(4_((1)))rarrCaSO_(4_((s)))+2HCl_((1))`