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An electric iron rated 750 W is operated...

An electric iron rated 750 W is operated for 2 hours/day. How much energy is consumed by the electric iron for 30 days ?

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Data : P=750 W,t= `2("hours")/("day")` for 30 days
The energy consumed =P t =`750xx2xx30`
`=1500xx30`
`=45000 W *h`
`=45 kW*h`
The energy consumed by the electric iron by 30 days =45 `k W*h`
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