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A potential differnce of 100 V is applie...

A potential differnce of 100 V is applied across a resistor of resistance `50Omega` for 6 minutes and 58 seconds . Find the heat produced in Joule

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Data : V=100 V, R =50 `Omega , t=6` minutes and 58 seconds. `=(6xx60 +58)s=(360+58)s =418 s, H= ?`
`H=(V^(2)t)/(R)=((100V)^(2)xx418s)/(50 Omega)`
`(100xx100x418)/(50)J=200xx418 J`
`=83600 J`
Heat generated =83600 Joules .
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