Principle of heat exchange:

Explanation

Suppose two objects A and B at different temperature `T_(1)` and `T_(2)` respectively are enclosed in a box of heat resistant material as shown in figure.

Let `m_(1) `= mass of A, `m_(2)` = mass of B, `c_(1) = ` specific heat capacity of A, `c_(2)=` specific heat capacity of B and T = common temperature attained by A and B after the heat exchange between A and B. Here,no heatleaves the box or enters the box from outside. Hence, if` T_(1) gt T_(2)`, heat energy lost by `A( Q_(1))` = heat energy gained by `B(Q_(2))`.
`:. m_(1)c_(1)(T_(1)-T) = m_(2)c_(2)(T-T_(2))`