If `a in R and (alpha - 2)x^2 + 8x + alpha + 4 lt 0, AA x in in R`, then `alpha` cannot be

If alpha gt (1)/(sin^(6)x+cos^(6)x) AA x in R , then alpha can be

If alpha gt (1)/(sin^(6)x+cos^(6)x) AA x in R , then alpha can be

If x in R " and "alpha=(x^(2))/(1+x^(4)) , then alpha lies in the interval

If x in R " and "alpha=(x^(2))/(1+x^(4)) , then alpha lies in the interval

If x in R and alpha = (x^(2))/((1+x^(4))) , thens

If sin x + sin y> = cos alpha cos x, AA x in R then sin y + cos alpha =

A function f : R rarr R is defined as f(x) = (alpha x^2 + 6x - 8 )/(alpha + 6x - 8x^2) . Find the set of values of alpha for which is onto.

Eliminate alpha , if x = r cos alpha , y = r sin alpha .

Eliminate alpha , if x = r cos alpha , y = r sin alpha .

If f:R rarr R,f(x)=(alpha x^(2)+6x-8)/(alpha+6x-8x^(2)) is onto then alpha in