A positive charge `q` is placed in front of a conducting solid cube at a distance `d` from its centre. Find the electric field at the centre of the cube due to the charges appearing on its surface.

Options

A. `(q)/(4piepsilon_(0)d^(2))` towards the charge `q`
B. `(q)/(4piepsilon_(0)d^(2))` away from the charge `q`
C. zero
D. can't be found

Answer

A

Explanation

Electric field at `C` due to `q`

`E= (kq)/(d^(2))` away from `q`.
As net field at `C` is zero, so field at `C` due to induced charges should be opposite to `E`.