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Two positive ions , each carrying a char...

Two positive ions , each carrying a charge `q` , are separated by a distance `d`.If `F` is the force of repulsion between the ions , the number of electrons missing from each ion will be (`e` being the charge on an electron)

A

`(4piepsilon_(0)Fd^(2))/(e^(2))`

B

`sqrt((4piepsilon_(0)Fe^(2))/(d^(2)))`

C

`sqrt((4piepsilon_(0)Fd^(2))/(e^(2)))`

D

`(4piepsilon_(0)Fd^(2))/(q^(2))`

Text Solution

Verified by Experts

The correct Answer is:
c

Two positive ions each carrying a charge `q` are kept at a distance `d`, then it is found that force of repulsion between them is
`F= (kqq)/(d^(2))= (1)/(4epsilon_(0)) (qq)/(d^(2))`
where `q= n e :. F= (1)/(4epsilon_(0)) (n^(2)e^(2))/(d^(2))`
`implies n= sqrt((4pi epsilon_(0)Fd^(2))/(e^(2)))`
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