A potential difference of `600 volts` is applied across the plates of a parallel plate consenser . The separation between the plates is `3mm`. An electron projected vertically, parallel to the plates , with a velocity of `2 xx 10^(6) m//sec` moves underflected between the plates. Find the magnitude and direction of the magnetic field in the region between the condenser plates. ( Neglect the edge effects). ( Charge of the electron `= -1.6xx10^(-19) coulomb)

Options

A. `0.1T`
B. `0.2T`
C. `2xx10^(6)T`
D. `600T`

Answer

A

Explanation

`B=E/v`
`(600V)/(3xx10^(-3)m)xx(1)/(2xx10^(6)ms^(-1))`
`10^(-1)T=0.1T`