If a particle of charge `10^(-12)` coulomb moving along the `hat(x)`-direction with a velocity `10^(5)m//s` experiences a force of `10^(-10)` newton in `hat(y)`-direction due to magnetic field. Then the minimum magnetic field is

Options

A. `6.25xx10^(3)` tesla in `hat(z)`-direction
B. `10^(-15)` tesla in `hat(z)`-direction
C. `6.25xx10^(-3)` tesla in `hat(z)` direction
D. `10^(-3)` tesla in `hat(z)`-direction

Answer

D

Explanation

`F=qvB sin thetaimpliesB=(f)/(qvsin theta)`
`B_(min)=(F)/(qv)` (when `theta=90^(@)`)
`:. B_(min)=(F)/(qv)=(10^(-10))/(10^(-12)xx10^(5))=10^(-3)tesla`
in `hat(z)`-direction.