Two particles `A and B` of masses ` m_(A) and m_(B)` respectively and having the same charge are moving in a plane . The speeds of the particles are ` v_(A) and v_(B)` respectively and the trajectories are as shown in the figure. Then

Options

A. `m_(A)v_(A) lt m_(B)v_(B)`
B. `m_(A)v_(A) gt m_(B)v_(B)`
C. `m_(A) lt m_(B )`and `v_(A) lt v_(B)`
D. `m_(A)=m_(B)` and `v_(A)=v_(B)`

Answer

B

Explanation

`r=(mv)/(qB)impliesrpropmv` (`q` and `B` are constants)
`:' r_(A)gtr_(B)impliesm_(A)v_(A)gtm_(B)v_(B)`