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A particle of specific charge q//m = (pi...

A particle of specific charge `q//m = (pi) C//kg` is projected from the origin towards positive x-axis with a velocity of `10 m//s` in a uniform magnetic field `vec(B) = -2 hat K` Tesla. The velocity `vec V` of the particle after time `t =1//6` s will be

A

`(5hati+5sqrt(3hatj))m//s`

B

`10hatjm//s`

C

`(5sqrt3hati-5hatj)m//s`

D

`-10hatjm//s`

Text Solution

Verified by Experts

The correct Answer is:
A
Time period `aT=2pi(m)/(qB)=1s`

Thus the particle will be at `P` after `t=(1)/(6)s`
`vecV=10(cos60hati+sin60hatj)=5(hati+sqrt3hatj)m//s`
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A2Z-SOURCE AND EFFECT OF MAGNETIC FIELD-Section D - Chapter End Test
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