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A particle with charge `q`, moving with a momentum `p`, enters a uniform magnetic field normally. The magnetic field has magnitude `B` and is confined to a region of width `d`, where `dlt(p)/(Bq)`. If the particle is deflected by an angle `theta` in crossing the field then

A

`sintheta=(Bqd)/(p)`

B

`sintheta=(p)/(Bqd)`

C

`sintheta=(Bp)/(qd)`

D

`sintheta=(pd)/(Bq)`

Text Solution

Verified by Experts

The correct Answer is:
A

From figure it is clear that
`sintheta=(d)/(r )` also `r=(p)/(qB)`
`:. Sintheta=(Bqd)/(p)`
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