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Two thin long parallel wires separated by a distance `b` are carrying a current `i` amp each . The magnitude of the force per unit length exerted by one wire on the other is

A

`(mu_(0)i^(2))/(b^(2))`

B

`(mu_(0)i^(2))/(2pib)`

C

`(mu_(0)i)/(2pib)`

D

`(mu_(0)i)/(2pib^(2))`

Text Solution

Verified by Experts

The correct Answer is:
B

Force per unit length`=(mu_(0))/(4pi).(2i_(1)i_(2))/(r)=(mu_(0))/(2pi).(i^(2))/(b)`
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