Two long parallel copper wires carry currents of `5 A` each in opposite directions. If the wires are separated by a distance of ` 0.5m` , then the force between the two wires is

Options

A. `10^(-5)N`, attractive
B. `10^(-5)N` repulsive
C. `2xx10^(-5)N`, attractive
D. `2xx10^(-5)N`,repulsive

Answer

B

Explanation

`F=10^(-7)(2i_(1)i_(2))/(a)=10^(-7)xx(2xx5xx5)/(0.5)=10^(-5)N` (Repulsive)