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Two long conductors, separated by a distance `d` carry current `I_(1) and I_(2)` in the same direction . They exert a force `F` on each other. Now the current in one of them is increased to two times and its direction is reversed . The distance is also increased to `3d`. The new value of the force between them is

A

`-2F`

B

`(F)//(3)`

C

`(2F)//(3)`

D

`(-F)//(3)`

Text Solution

Verified by Experts

The correct Answer is:
C

`Fprop(i_(1)i_(2))/(a)`, Since one of the current increase two times and distance increases three times, so force become `(2)/(3)` times. Also due to the reversal of direction current force becomes negative.
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