Three long, straight parallel wires carrying current, are arranged as shown in figure. The force experienced by a `25cm` length of wire `C` is

Options

A. `10^(-3)N`
B. `2.5xx10^(-3)N`
C. Zero
D. `1.5xx10^(-3)N`

Answer

C

Explanation

Force on wire `C` due to wire `D`
`F_(D)=10^(-7)xx(2xx30xx10)/(2xx10^(-2))xx25xx10^(-2)=5xx10^(-4)N`

Force on wire `C` due to wire `G`
`F_(G)=10^(-7)xx(2xx20xx10)/(2xx10^(-2))xx25xx10^(-2)=5xx10^(-4)N` (Towards left)
`implies` Net force on wire `C` is `F_("net")=F_(D)-F_(G)=0`