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A conducting rod of length l and mass m is moving down a smooth inclined plane of inclination `theta` with constant i is flowing in the conductor in a direction perpendicular to paper inwards. A vertically upward magnetic field `vec B` exists in space. Then, magnitude of magnetic field `vec B` is

A

`(mg)/(il)sintheta`

B

`(mg)/(il)tantheta`

C

`(mgcostheta)/(il)`

D

`(mg)/(ilsintheta)`

Text Solution

Verified by Experts

The correct Answer is:
B
Magnetic force acts in the direction shown in figure below:

Road will move downwards with constant velocity if net force on it is zero.
or `F_(m)costheta=mgsintheta`
or `ilambdaBcostheta=mgsintheta`
` implies B=((mg)/(il))tantheta`
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