A current carrying loop is free to turn in a uniform magnetic field.The loop will then come into equilibrium when its plane is inclined at

Options

A. `0^(@)` to the direction of the field
B. `45^(@)` to the direction of the field
C. `90^(@)` to the direction of the field
D. `135^(@)` to the direction of the field

Answer

C

Explanation

In equilibrium angle between `vecM` and `vecB` is zero. It is happened, when plane of the coil is perpendicular to `vecB`