A particle carrying a charge equal to `100` times the charge on an electron is rotating per second in a circular path of radius `0.8 metre`. The value of the magnetic field produced at the centre will be (`mu_(0)=` permeability for vacuum)

Options

A. `10^(-7)//mu_(0)`
B. `10^(-17)mu_(0)`
C. `10^(-6)//mu_(0)`
D. `10^(-7)mu_(0)`

Answer

B

Explanation

Given that `q=100e, r=0.8 m` and `f=1sec^(-1)`
`:. 1=(q)/(t)=qf=100exx1`
Now `B=(mu_(0)Imu_(0)(100 exx1))/(2I 2xx0.8)`
`=(mu_(0)xx100xx(1.6xx10^(-19)))/1.6xxI`
`=10^(-17) mu_(0)`