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Two parallel wires carrying equal currents `i_(1)` and `i_(2)` with `i_(1)gti_(2)`. When the current are in the same direction, the `10 mT`. If the direction of `i_(2)` is reversed, the field becomes `30 mT`. The ratio `i_(1)//i_(2)` is

A

`4`

B

`3`

C

`2`

D

`1`

Text Solution

Verified by Experts

The correct Answer is:
C

`10mT=(mu_(0))/(2pi(r//2)) (i_(1)-i_(2))`
`30 mT=(mu_(0))/(2pi(r//2)) (i_(1)+i_(2))`
Dividing : `i_(1)//i_(2)=2`
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