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The magnetic field at the centre of an e...

The magnetic field at the centre of an equilateral triangular loop of side 2L and carrying a current i is

A

`(9mu_(0)i)/(4piL)`

B

`(3sqrt(3)mu_(0)i)/(4piL)`

C

`(2sqrt(3)mu_(0)i)/(piL)`

D

`(3mu_(0)i)/(4piL)`

Text Solution

Verified by Experts

The correct Answer is:
A
Magnetic field at `O` is
`B=3[(mu_(0))/(4pi) (i/r)(sin60^(@)+sin60^(@))]`

`=3((mu_(0))/(4pi))(i)((sqrt(3))/2)(sqrt(3))`
`=(9mu_(0)i)/(4piL)`
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