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A long straight wire carrying current of `30 A` is placed in an external uniform magnetic field of induction `4xx10^(4) T`. The magnetic field is acting parallel to the direction of current. The magnitude of the resultant magnetic inuduction in tesla at a point `2.0 cm` away form the wire is

A

`10^(-4)`

B

`3xx10^(-4)`

C

`5xx10^(-4)`

D

`6xx10^(-4)`

Text Solution

Verified by Experts

The correct Answer is:
C

`B_(1) = 4xx10^(-4) T`

`B_(2) = 10^(-7) xx (2xx30)/(2xx10^(-2)) = 3xx10^(-4) T`
`:. B_(net) = sqrt(B_(1)^(2) + B_(1)^(2)) = 5xx10^(-4) T`
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