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A square loop ABCD, carrying a current I...

A square loop `ABCD`, carrying a current `I_(2)` is placed near and coplanar with a long straight conductor `XY`, carrying a current `I_(1)` as shown in Figure. The net force on the loop will be

A

`(mu_(0) I_(1) I_(2))/(2pi)`

B

`(2mu_(0) I_(1) I_(2))/(3pi)`

C

`(mu_(0) I_(1) I_(2)L)/(2pi)`

D

`(2mu_(0) I_(1) I_(2)L)/(3pi)`

Text Solution

Verified by Experts

The correct Answer is:
B

Force on side `AB` due to current in long wire
`F_(1) = (mu_(0))/(4pi) (2 I_(1) I_(2) L)/(41pi (L//2)) = (mu_(0) I_(1) I_(2))/(pi)` (attractive).
Force on side `CD`
`F_(1) = (mu_(0))/(4pi) (2 I_(1) I_(2) L)/((3L//2)) = (mu_(0) I_(1) I_(2))/(3pi)` (repulsive)
`:.` Net force on the loop `= F_(1) - F_(2)`
`= (mu_(0) I_(1) I_(2))/(pi) [1 - (1)/(3)] = (2)/(3) (mu_(0) I_(1) I_(2))/(pi)` (attractive)
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Knowledge Check

  • A square loop ABCD , carrying a current I, is placed near and coplanar with a long straight conductor XY carrying a current I.

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