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Two thin long parallel wires seperated ...

Two thin long parallel wires seperated by a distance 'b' are carrying a current ' I' amp each . The magnitude of the force3 per unit length exerted by one wire on the other is

A

`(mu_(0) i^(2))/(b^(2))`

B

`(mu_(0) i^(2))/(2pi b)`

C

`(mu_(0) i)/(2pi b)`

D

`(mu_(0) i)/(2pi b^(2))`

Text Solution

Verified by Experts

The correct Answer is:
B

Force per unit length `= (mu_(0))/(4pi) , (2i_(1) i_(2))/(r) = (mu_(0))/(2pi), (i^(2))/(b)`
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