The charge on a particle `Y` is double the charge on particle `X`.These two particles `X` and `Y` after being accelerated through the same potential difference enter a region of uniform magnetic field and describe circular paths of radii `R_(1)` and `R_(2)` respectively. The ratio of the mass of `X` to that of `Y` is

Options

A. `((R_(1))/(R_(2)))^(1//2)`
B. `(R_(2))/(R_(1))`
C. `((R_(1))/(R_(2)))^(2)`
D. `(R_(1))/(R_(2))`

Answer

C

Explanation

`r = (sqrt(2mk))/(qB) = (1)/(B) sqrt((2mV)/(q)) implies r prop (m_(1))/(m_(2)) =((R_(2))/(R_(2)))^(2)`