A proton `(mass = 1.67xx10^(-27) kg` and charge `1.6xx10^(-19) C)` enters perpendicular to a magentic field of intensity `2 weber//m^(2)` with a speed of `2.6xx10^(7) m//sec`. The acceleration of the proton should be

Options

A. `6.5xx10^(15) m//sec^(2)`
B. `6.5xx10^(13) m//sec^(2)`
C. `6.5xx10^(11) m//sec^(2)`
D. `6.5xx10^(9) m//sec^(2)`

Answer

A

Explanation

`F = ma = qvB`
`implies a = (qvB)/(m) = (1.6xx10^(-19)xx2xx3.4xx10^(7))/(1.67xx10^(-27))`
`= 6.5xx10^(15) m//sec^(2)`