An `alpha` particle travels in a circular path of radius `0.45 m` in a magnetic field `B = 1.2 Wb//m^(2)` with a speed of `2.6xx10^(7) m//sec`. The `alpha` particle is

Options

A. `1.1xx10^(-5) sec`
B. `1.1xx10^(-6) sec`
C. `1.1xx10^(-7) sec`
D. `1.1xx10^(-8) sec`

Answer

C

Explanation

`T = (2pi m)/(qB) = (2pi r)/(v) = (2xx3.14xx0.45)/(2.6xx10^(7)) = 1.08xx10^(-7)` sec