The magnitude of the earth's magnetic field at a place is `B_(0)` and the angle of dip is `varphi` . A horizontal conductor of length `l` , lying north-south, moves eastward with a velocity `v` . The emf induced across the rod is

Options

A. zero
B. `B_(0)l v sin varphi`
C. `B_(0)lv`
D. `B_(0)l v cos varphi`

Answer

B

Explanation

When a conductor lying along the magnetic north south, moves eastwards it will cut vertical component of `B_(0)`. So induced emf
`e=vB_(V)l=v(B_(0)sindeltal)=B_(0)l sin delta`.