A conducting rod of length `2l` is rotating with constant angular speed `w` about its perpendicular bisector. A uniform magnetic field `B` exists parallel to the axis of rotation. The e.m.f. induced between two ends of the rod is

Options

A. `Bomegal^(2)`
B. `(1)/(2)Bomegal^(2)`
C. `(1)/(8)Bomegal^(2)`
D. zero

Answer

D

Explanation

Potential difference between
`O and A is V_(0)-V_(A)=(1)/(2)Bl^(2)omega`
`O and B is V_(0)-V_(B)=(1)/(2)Bl^(2)omega`
so `V_(A)-V_(E)=0`