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A conducting rod of length L=0.1 m is mo...

A conducting rod of length `L=0.1 m` is moving with a uniform sped `v=0.2m//s` on conducting rail a magnetic field `B=0.5T` as shown. On one side, the end of the rails is connected to a capacitor of capacitance `C=20muF`. Then, the charge on the capacitor's plates are

A

`q_(A)=+80 muC and q_(B)=-80 muC`

B

`q_(A)=-80 muC and q_(B)=+80 muC`

C

`q_(A)=0=q_(B)`

D

Charge stored in the capacitor increase exponentially with time

Text Solution

Verified by Experts

The correct Answer is:
A
`Q=CV=C(Bvl)=10xx10^(-6)xx4xx2xx1=80mC`
According to fleming's right hand rule induced crrent flows from `Q` to `P`. Hence `P` is at higer potential and `Q` is at lower potential. Therefore `A` is positively charge and `B` is negatively charged.
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