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The current passing through a choke coil...

The current passing through a choke coil of `5` henry is decreasing at the rate of `2 ampere//sec`. The e.m.f. developing across the coil is

A

`10 V`

B

`-10V`

C

`2.5 V`

D

`-2.5 V`

Text Solution

Verified by Experts

The correct Answer is:
A

Given `(di)/(dt)=2A//sec.,L=5H`
`:.e=L(di)/(dt)=5xx2=10V`
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