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If a current of 3.0 amperes flowing in ...

If a current of `3.0` amperes flowing in the primary coil is reduced to zero in `0.001` second, then the induced e.m.f. in the secondary coil is `15000 "volts"`. The mutual inductance between the two coils is

A

`0.5` Henry

B

`5 ` Henry

C

`1.5 ` Henry

D

`10 ` Henry

Text Solution

Verified by Experts

The correct Answer is:
B
`e=e=M(di)/(dt)impliesM=(15000)/(3)xx0.001=5H`
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